Solutions to Second In - Class Exam
نویسنده
چکیده
Solution. The equation is linear and is already in normal form. The coefficient of u is undefined at t = 0 and is continuous elsewhere. The coefficient of u is undefined at t = −6 and is continuous elsewhere. The forcing is undefined at t = 2 and is continuous elsewhere. Therefore the interval of definition is (−6, 0) because • the initial time t = −3 is in the interval (−6, 0), • all the coefficients and the forcing are continuous over the interval (−6, 0), • at t = −6 the coefficient of u is undefined, • at t = 0 the coefficient of u is undefined.
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تاریخ انتشار 2013